Chiki4idn
Answered

Get the best answers to your questions with the help of IDNLearn.com's experts. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.

Calculate the ratio of change in the mass of the molecules of a gas to the initial mass, if its
speed is reduced to half and the ratio of initial and final pressure is 3:4.

Hint : P =1/3 M/V.v²
​

Sagot :

Lucky75idn

Answer:

Required Answer is as follows :-

  • [tex]\sf \dfrac{P _{i}}{ P_{f}} = \dfrac{3}{4}[/tex]

  • 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²

  • ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²

  • ¾ = m₁ × (V)²/m₂ × (V²/4)

  • ¾ = m₁/m₂ × 4

  • m₂ = 4 × 4/3 = 16/3m₁

[tex]\bold{   }[/tex] 

Now,

  • ∆m = m₂ - m₁
  • ∆m = 16m₂/3 - m₁ = 13m₁/3
  • Ratio = (13m₁/3)/ m₁
  • Ratio = 13/3

Ratio = 13:3

[tex]\bold{   }[/tex] 

Know More :-

Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.[tex]\bold{   }[/tex] 

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.