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There are five lines of length 1, 3, 5, 7, 9. Take randomly three straight segments from those five lines. Calculate the probability that the three selected segments can form a triangle

Sagot :

Answer:

  • 3/10 or 30%

Step-by-step explanation:

Given the segments:

  • 1, 3, 5, 7, 9

Number of combinations of 3 line segments out of 5:

  • 5C3 = 5!/3!2! = 10

Triangle can be formed if only any side is smaller than the sum of the other  two sides.

Possible triangles:

  • (3,5,7), (3,7,9) and (5,7,9) - the number is 3

Probability:

  • Favorable outcomes/total outcomes = 3/10 or 30%