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[tex] - 9x + 3y - 27 = 0 \\ a = - 9 \\ b = 3 \\ c = 0 \\ {b}^{2} - 4ac = 9 - 4( - 9)( - 27) = 0 \\ x = \frac{ - b}{2a} = \frac{ - 3}{ - 18} = \frac{1}{6} \\ x = \frac{1}{6} \\ y = ( - 9 \times \frac{1}{6} ) + 3y = 27 \\ \frac{ - 3}{2} + 3y = 27 \\ 3y = 27 + \frac{3}{2 } \\ 3y = \frac{57}{2} \\ y = \frac{57}{6} = \frac{19}{2} \\ [/tex]
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