Answered

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To what volume will you have to dilute 60.0 mL of a 9 M HCl solution to
make a 0.35 M HCl solution? *

Sagot :

Boffeemadrididn

Answer:

[tex]1542.85\ \text{mL}[/tex]

Explanation:

[tex]V_1[/tex] = Volume of HCl = 60 mL

[tex]C_1[/tex] = Initial concentration of HCl = 9 M

[tex]C_2[/tex] = Final concetration of HCl = 0.35 M

[tex]V_2[/tex] = Volume to be diluted

We have the relation

[tex]\dfrac{C_1}{C_2}=\dfrac{V_2}{V_1}\\\Rightarrow \dfrac{9}{0.35}=\dfrac{V_2}{60}\\\Rightarrow V_2=\dfrac{9}{0.35}\times 60\\\Rightarrow V_2=1542.85\ \text{mL}[/tex]

The required volume is [tex]1542.85\ \text{mL}[/tex].

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