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Given the diagram below, if P is the incenter of AJRL,
PO = 31, KM = 34, and PL = 48, find each measure.
13. PM
14. KN

15. OL
16. KP

Given The Diagram Below If P Is The Incenter Of AJRL PO 31 KM 34 And PL 48 Find Each Measure 13 PM 14 KN 15 OL 16 KP class=

Sagot :

Answer:

13. PM=31 14. KN=34 15. OL=36.6 KP=46

Step-by-step explanation:

13. PM≅PN≅PO 14.KM≅KN

15.[tex]x^{2}+31^{2}=48^{2}[/tex]

[tex]x^{2} +961=2304\\[/tex]

subtract 961 from both sides

[tex]\sqrt{x^2} =\sqrt{1343}\\x=36.6[/tex]

16. [tex]31^{2} +34^{2}=x^{2}[/tex]

[tex]961+1156=x^{2}[/tex]

add 961 and 1156 together

[tex]\sqrt{2117^2} }=\sqrt{x^{2} }[/tex][tex]x=46.0[/tex]

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