Ariannaajones12004idn
Answered

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Sickle-cell anemia is a recessive trait in humans. In order to express the disease, an affected individual must inherit two recessive alleles (ss).

What is the probability that the offspring of two heterozygous parents will also be heterozygous?

Choose 1 answer:

(choice A)
A


(choice B)
B
[tex]\frac{1}{4}[/tex]

(choice C)
C
[tex]\frac{1}{2}[/tex]

(choice D)
D
[tex]\frac{3}{4}[/tex]

(choice E)
E
[tex]\frac{4}{4}[/tex]

Sagot :

Answer:

1/4 will have ss trait

Explanation:

other 2/4 will be carrier(Ss) and other 1/4 will have both dominant trait (SS)

Ettabeafunkymonkeyidn

Answer:

B. 1/2

Explanation:

The genotypes of the parents are Ss and Ss. We know this because Heterozygous basically means different alleles. The punnet square of this problem will show that the possible genes given to the offspring are SS (capital letters mean dominant. keep in mind that sickle-cell anemia is a recessive trait, meaning it is written in lowercase), Ss, Ss, or ss. So this means the offspring will have a 1/2 chance of becoming heterozygous (Ss).

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