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A ball is dropped from a building taking 3sec to fall to the ground. Calculate:
Speed ​​when falling to the ground
The height of the building


Sagot :

Answer:

Vf = 29.4 m/s

h = 44.1 m

Explanation:

Data:

  • Initial Velocity (Vo) = 0 m/s
  • Gravity (g) = 9.8 m/s²
  • Time (t) = 3 s
  • Final Velocity (Vf) = ?
  • Height (h) = ?

==================================================================

Final Velocity

Use formula:

  • Vf = g * t

Replace:

  • Vf = 9.8 m/s² * 3s

Multiply:

  • Vf = 29.4 m/s

==================================================================

Height

Use formula:

  • [tex]\boxed{h=\frac{g*(t)^{2}}{2}}[/tex]

Replace:

  • [tex]\boxed{h=\frac{9.8\frac{m}{s^{2}}*(3s)^{2}}{2}}[/tex]

Multiply time squared:

  • [tex]\boxed{h=\frac{9.8\frac{m}{s^{2}}*9s^{2}}{2}}[/tex]

Simplify the s², and multiply in the numerator:

  • [tex]\boxed{h=\frac{88.2m}{2}}[/tex]

It divides:

  • [tex]\boxed{h=44.1\ m}[/tex]

What is the velocity when falling to the ground?

The final velocity is 29.4 meters per seconds.

How high is the building?

The height of the building is 44.1 meters.