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Sagot :
Answer:
The numbers can be either -8,-7,-6, or 6, 7, 8.
n(n−1)(n+1)=16(n−1+n+n+1)
⟹n(n2−1)=16×3n
⟹n(n2−1)n=48nn
⟹(n2−1)−48=48−48
⟹n2−49=0
⟶(n−7)(n+7)=0
n can be 7 or −7 , so the numbers can be either −8,−7,−6
Or
6,7,8
Step-by-step explanation:
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