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How many grams are in 1.30 x 10^24 formula units of Ca(NO3)2?
A. 151 g
B. 354 g
C. 294 g
D. 416 g


How Many Grams Are In 130 X 1024 Formula Units Of CaNO32 A 151 G B 354 G C 294 G D 416 G class=

Sagot :

Answer:

354 gram

Explanation:

No of formula units = no of moles × Avogadro's number

Number of moles = no of formula units/ Avogadro's number

No of moles = 1.30×10^24/60.02×10^23

No of moles = 2.159 moles

Mo of moles = mass in gram/ molar mass

Mass in gram = no of moles× molar mass

Mass in gram =2.159×164

Mass in gram = 354.15 gram

The grams that are present in [tex]1.30 * 10^{24}[/tex] formula units of [tex]Ca(NO_3)_2[/tex] is 354 gram that can be calculated using number of moles.

(B) 354 g

One mole:

A mole is defined as [tex]6.02214076 * 10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others.

No. of formula units = no of moles × Avogadro's number

Number of moles = no of formula units/ Avogadro's number

No. of moles = [tex]1.30*10^{24}/6.022*10^{23}[/tex]

No. of moles = 2.159 moles

The Number of moles is defined as the given mass over molar mass.

No. of moles = Mass / Molar mass

Mass = no. of moles× molar mass

Mass =2.159×164

Mass = 354.15 gram

Thus, option B is correct.

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