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V2 - 15 = -2v Solve the Quadratic. What are the 2 solutions?

Sagot :

Lublanaidn

Answer:

v=-5 and v=3

Step-by-step explanation:

We are given that

[tex]v^2-15=-2v[/tex]

We have to find  two solutions of quadratic equation.

[tex]v^2+2v-15=0[/tex]

Using addition property of equality

[tex]v^2+5v-3v-15=0[/tex]   (By using factorization method)

[tex]v(v+5)-3(v+5)=0[/tex]

[tex](v+5)(v-3)=0[/tex]

Substitute each factor equal to 0

[tex]v+5=0[/tex] and [tex]v-3=0[/tex]

[tex]v=-5[/tex] and [tex]v=3[/tex]

Hence, two solutions of quadratic equation are

v=-5 and v=3

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