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Find the square root of 25x^2-40xy+16y^2​

Sagot :

The square root of [tex]25x^2-40xy+16y^2[/tex] is 5x - 4y.

Given that,

  • The quadratic equation is [tex]25x^2-40xy+16y^2[/tex].
  • We need to find out the square root.

Based on the above information, the calculation is as follows:

[tex]= 25x^2-40xy+16y^2\\\\= (5x)^2 - (2\times 5x \times 4y) + (4y)^2\\\\= (5x - 4y)^2\\\\= \sqrt{ (5x - 4y)^2}[/tex]

= 5x - 4y

Therefore we can conclude that the square root of [tex]25x^2-40xy+16y^2[/tex] is 5x - 4y.

Learn more: brainly.com/question/9664917

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