Answered

Get the most out of your questions with IDNLearn.com's extensive resources. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

If 23.17 g of beryllium (Be) reacts with water at standard temperature and pressure,
how many liters of hydrogen (H2) are produced?

Sagot :

Ardni313idn

Volume of H2 produced = 57.6576 L

Further explanation

Given

23.17 g Be

Required

Volume of H2

Solution

Reaction

Be(s)+H2O(g)→BeO(s)+H2(g)

mol Be :

= 23.17 g : 9 g/mol

= 2.574

From the equation, mol H2 : mol Be = 1 : 1, so mol H2 = 2.574

Volume H2(assumed at STP, 1 mol=22.4 L) :

= 2.574 x 22.4 L

= 57.6576 L

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.