Answer:
The values of x are:
[tex]x=3,\:x=7[/tex]
Step-by-step explanation:
Given the expression
[tex](x-2)^2-6(x-2)+5=0[/tex]
Expand (x - 2)² = x² -4x + 4
[tex]x^2-4x+4-6\left(x-2\right)+5=0[/tex]
Expand: -6(x - 2) = -6x + 12
[tex]x^2-4x+4-6x+12+5=0[/tex]
simplifying
[tex]x^2-10x+21=0[/tex]
Factor x² -10x + 21: (x - 3) (x - 7)
[tex]\left(x-3\right)\left(x-7\right)=0[/tex]
Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)
[tex]x-3=0\quad \mathrm{or}\quad \:x-7=0[/tex]
solving x - 3 = 0
x - 3 = 0
Adding 3 to both sides
[tex]x-3+3=0+3[/tex]
simplify
x = 3
solving x - 7 = 0
x - 7 = 0
Adding 7 to both sides
[tex]x-7+7=0+7[/tex]
Simplify
x = 7
Therefore, the values of x are:
[tex]x=3,\:x=7[/tex]
