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A spring has a force constant of 40000 N/m.
How far must it be stretched for its potential energy to be 42 J?
Answer in units of m

Sagot :

QuasarJoseidn

Answer:

0.05m

Explanation:

Given parameters:

Force constant of the spring  = 40000N/m

Potential energy  = 42J

Unknown:

Extension  = ?

Solution:

To solve this problem, use the expression below:

           E.PE  = [tex]\frac{1}{2}[/tex] k e²  

k is spring constant

e is the extension

              42  =  [tex]\frac{1}{2}[/tex]  x 40000 x e²  

               e  = 0.05m

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