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Moles of NH3 = 0.3 moles
N2 + 3H2 → 2NH3
4.2021 g of N2
Required
moles of NH3
Solution
mol N2 :
= 4.2021 g : 28 g/mol
= 0.15
From the equation, mol NH3 :
= 2/1 x mol N2
= 2/1 x 0.15
= 0.3 moles