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Sagot :
Answer:
0.5987 = 59.87% probability that every cell in the battery pack will last for at least 10,000 charge-discharge cycles
Step-by-step explanation:
For each cell, there are only two possible outcomes. Either it will least for at least 10,000 charge-discharge cycles, or it will not. Cells are independent of each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
10 individual cells.
This means that [tex]n = 10[/tex]
95% probability
This means that [tex]p = 0.95[/tex]
What is the probability that every cell in the battery pack will last for at least 10,000 charge-discharge cycles
This is P(X = 10).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987[/tex]
0.5987 = 59.87% probability that every cell in the battery pack will last for at least 10,000 charge-discharge cycles
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