IDNLearn.com makes it easy to find the right answers to your questions. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

What must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 640 N/C

Sagot :

Answer:

[tex]q=-2.26\times 10^{-5}\ C[/tex]

Explanation:

Given that,

The mass of a particle, m = 1.48 g = 0.00148 kg

The electric field, E = 640 N/C

We need to find the charge of the particle when placed in a downward-directed electric field.

The force of gravity is balanced by the electric force such that,

mg = qE

Where

q is the charge of the particle

[tex]q=\dfrac{mg}{E}\\\\q=\dfrac{0.00148\times 9.8}{640}\\\\q=2.26\times 10^{-5}\ C[/tex]

q must be negative, the force must be upward (opposite direction of the electric field).