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Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-6, -4),A(−6,−4),A, left parenthesis, minus, 6, comma, minus, 4, right parenthesis, comma B(-4,-4)B(−4,−4)B, left parenthesis, minus, 4, comma, minus, 4, right parenthesis, C(-4, -2)C(−4,−2)C, left parenthesis, minus, 4, comma, minus, 2, right parenthesis, and D(-6, -2)D(−6,−2)D, left parenthesis, minus, 6, comma, minus, 2, right parenthesis.

What is the perimeter of rectangle ABCDABCDA, B, C, D?

units

Rectangle ABCDABCDA B C D Is Graphed In The Coordinate Plane The Following Are The Vertices Of The Rectangle A6 4A64A Left Parenthesis Minus 6 Comma Minus 4 Rig class=

Sagot :

MrRoyalidn

The perimeter of the rectangle is 8 units

The coordinates of the rectangle is given as:

[tex]A = (-6,-4)[/tex]

[tex]B = (-4,-4)[/tex]

[tex]C = (-4,-2)[/tex]

[tex]D = (-6,-2)[/tex]

Start by calculating the distance between the vertices using the following distance formula

[tex]d=\sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]

So, we have:

[tex]AB=\sqrt{(-6 --4)^2 + (-4 --4)^2}[/tex]

[tex]AB=\sqrt{4}[/tex]

[tex]AB=2[/tex]

[tex]BC=\sqrt{(-4 --4)^2 + (-4 --2)^2}[/tex]

[tex]BC=\sqrt{4}[/tex]

[tex]BC=2[/tex]

[tex]CD=\sqrt{(-4 --6)^2 + (-2 --2)^2}[/tex]

[tex]CD=\sqrt{4}[/tex]

[tex]CD=2[/tex]

[tex]DA=\sqrt{(-6 --6)^2 + (-2 --4)^2}[/tex]

[tex]DA=\sqrt{4}[/tex]

[tex]DA = 2[/tex]

So, the perimeter of the rectangle is:

[tex]P =AB + BC + CD + DA[/tex]

This gives

[tex]P= 2 + 2+2+2[/tex]

[tex]P= 8[/tex]

Hence, the perimeter of the rectangle is 8 units

Read more about perimeters at:

https://brainly.com/question/397857

Mirsalikhovhidn

Answer:

P=8

Step-by-step explanation:

Just like that guy said

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