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An 80 N rightward force is applied to a 10 kg object to accelerate it to the right.
The object encounters a friction force of 50 N.

Sagot :

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net force = 30 N

mass = 8.16 kg

acceleration = 3.68 m/s²

Further explanation

Given

80 N force applied

mass of object = 10 kg

Friction force = 50 N

Required

Net force

mass

acceleration

Solution

  • net force

Net force = force applied(to the right) - friction force(to the left)

Net force = 80 - 50 = 30 N

  • mass

Gravitational force(downward) : F = mg

m = F : g

m = 80 : 9.8

m = 8.16 kg

  • acceleration

a = F net / m

a = 30 / 8.16

a = 3.68 m/s²

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