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The new volume of the balloon : V₂ = 4.89 L
Given
V₁ = 4.96 L
T₁ = 6 + 273 = 279 K
T₂ = 2 + 273 = 275 K
Required
The new volume
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
Input the value :
V₂=V₁.T₂/T₁
V₂ = 4.96 x 275 / 279
V₂ = 4.89 L