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find the probability of getting a prime number on the dice and head on the coin when a dice is rolled and a coin is tossed simultaneously. ​

Sagot :

Answer:

1/4

Step-by-step explanation:

For a die,

the number of possible results is 6

The prime numbers are 2,3,5

the probability of getting a prime number is thus; 3/6 = 1/2

Tossing a coin, the probability of getting a head is also 1/2

So the probability of getting both on a single toss will be;

1/2 * 1/2 = 1/4

Cricetusidn

The probability of getting both on one toss will be "[tex]\frac{1}{4}[/tex]".

According to the question,

The number of possible results,

  • 6

Prime numbers,

  • 2, 3 and 5

Now,

The probability of getting a prime number will be:

= [tex]\frac{3}{6}[/tex]

= [tex]\frac{1}{2}[/tex]

then, by tossing the coin head's probability is "[tex]\frac{1}{2}[/tex]".

hence,

Getting both on single toss will be:

= [tex]\frac{1}{2}\times \frac{1}{2}[/tex]

= [tex]\frac{1}{4}[/tex]

Thus the above answer is right.

Learn more about probability here:

https://brainly.com/question/23276848

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