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Sagot :
x² - 10x + 10 = 0
Isolate the constant term
x² - 10x = -10
Complete the square
• coefficient of the x term: -10
• divide in half: -5
• square it: (-5)² = 5²
• add 5² to both sides, to complete the square and keep the equation balanced:
x² - 10x + 5² = -10 + 5²
(x-5)² = 15
Isolate the constant term
x² - 10x = -10
Complete the square
• coefficient of the x term: -10
• divide in half: -5
• square it: (-5)² = 5²
• add 5² to both sides, to complete the square and keep the equation balanced:
x² - 10x + 5² = -10 + 5²
(x-5)² = 15
Answer:
1) We can rewrite the equation as 15=(x-5)^2
2) The solutions to the equation are x=5±15
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