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If 0 is an angle in standard position and its terminal side passes through the point
(-7,24), find the exact value of sec 0 in simplest radical form.


Sagot :

Answer:

[tex] \frac { 5\sqrt{21} }{ - 7} [/tex]

Step-by-step explanation:

Firstly, let find some some other trig functions. We need to know all sides to know other trig functions. We know the horizontal side is -7 because it x-axis is at -7, it y-axis is at 24. so it vertical side is 24. Then we use the pythagorean theorem to find r

[tex] {7}^{2} + {24}^{2} = {r}^{2} [/tex]

49+576=

[tex] {c}^{2} [/tex]

525=c^2

[tex] \sqrt{525} = 5 \sqrt{21} [/tex]

So since we know that x= -7, y=24, r= 5 times sqr root of 21. We can find some trig functions. We can use function cosine here. Cosine equals

[tex] \frac{x}{r} [/tex]

cos=

[tex] \frac{ - 7}{5 \sqrt{21} } [/tex]

then we find secant which is the reciprocal of cos so we flip the numbers and that equals

[tex] \frac{5 \sqrt{21} }{ - 7} [/tex]