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in the diagram below of triangle C D E,F is a midpoint of C D and G is a midpoint of D E, if F G = 9x -59, C E = 34 - x, what is the measure of C E?

Sagot :

Atashinchiiiidn

Answer:

Hey, I'm not sure if my assumptions were correct or not because there is no diagram. I assumed the triangle to be equilateral, the two lines are parallel and the height of the triangle is 1.

Step-by-step explanation:

Since the triangle is parallel*, we can just use ratio and proportion.

[tex] \frac{rise}{run} = \frac{1}{34 - x} = \frac{0.5}{9x - 59} \\ \frac{1}{34 - x} = \frac{0.5}{9x - 59} \\ 1(9x - 59) = 0.5(34 - x) \\ 9x - 59 = 17 - .5x \\ 9x + 0.5x = 59 + 17 \\ 9.5x = 76 \\ x = \frac{76}{9.5} \\ x = 8[/tex]

Now that we had found the value of x, we will now substitute that to both equations to get the respective distances.

CE = 34 - x = 34 - 8 = 26

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