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Answer:
[tex]P_2=507.7torr[/tex]
Explanation:
Hello there!
In this case, when we have a gas that is undergoing a change in both pressure and temperature, we utilize the Gay-Lussac's equation as shown below:
[tex]\frac{T_2}{P_2}=\frac{T_1}{P_1}[/tex]
Thus, since we are given the initial pressure and temperature and the final temperature, we can compute the final pressure as shown below:
[tex]P_2=\frac{P_1}{T_1}*T_2[/tex]
So we plug in, by making sure the temperatures are in kelvins, to obtain:
[tex]P_2=\frac{550torr}{(117+273)K}*(87+273)K\\\\P_2=507.7torr[/tex]
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