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Answer:
center (-13,2) radius=9
Step-by-step explanation:
(x+13)^2+(y+2)^2=81
x=-13
y=-2
r=sq rt of 81
The center and radius of this circle [tex](x+13)^{2} +(y+2)^{2} = 81[/tex] is (h, k) = (-13, -2) and r = 9.
A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.
The equation of a circle in standard form,
[tex](x-h)^{2} +(y-k)^{2} = r^{2}[/tex]
Given equation of circle
[tex](x+13)^{2} +(y+2)^{2} = 81[/tex]..................(1)
By comparing the standard form of circle with equation 1, we get
(h, k) = (-13, -2) and
[tex]r^{2} = 81[/tex]
⇒ [tex]r = \sqrt{81}[/tex]
⇒ r = 9
Hence, the center and radius of this circle [tex](x+13)^{2} +(y+2)^{2} = 81[/tex] is (h, k) = (-13, -2) and r = 9.
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