Answer:
The height of Moyo is
[tex]\frac{67}{6}[/tex]
The height of Adamu is
[tex]\frac{13}{6}[/tex]
Step-by-step explanation:
Equations
To solve the problem, we assign the variable:
x = height of Moyo
Since Moyo is 9 units taller than Adamu:
x - 9 = height of Adamu
The difference of the squares of their heights is 120, thus:
[tex]x^2-(x - 9)^2=120[/tex]
Operating:
[tex]x^2-(x^2-18x+81)=120[/tex]
[tex]x^2-x^2+18x-81=120[/tex]
Simplifying:
[tex]18x-81=120[/tex]
Adding 81:
[tex]18x=120+81=201[/tex]
Dividing by 18:
[tex]x=\frac{201}{18}=\frac{67}{6}[/tex]
The height of Moyo is
[tex]\frac{67}{6}[/tex]
The height of Adamu is
[tex]\frac{67}{6}-9=\frac{13}{6}[/tex]
