AM28idn
Answered

Explore a diverse range of topics and get expert answers on IDNLearn.com. Get the information you need from our community of experts, who provide detailed and trustworthy answers.

Need help with question 3!
*please answer correctly*


A student increases the temperature of a 300cm3 balloon from 40°C to 110°C.

What will the new volume of the balloon be? Round your answer to one decimal point.

(To convert Celsius to kelvin, add 273.15)

Thank you!!!

Need Help With Question 3 Please Answer Correctly A Student Increases The Temperature Of A 300cm3 Balloon From 40C To 110C What Will The New Volume Of The Ballo class=

Sagot :

Answer:

[tex]V_2=367.06\ cm^3[/tex]

Explanation:

Charles law states that volume of the gas is directly proportional to the temperature i.e.

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

We ave,

V₁ = 300 cm³

T₁ = 40°C = 40 + 273.15 = 313.15  K

T₂ = 110°C = 110 + 273.15 = 383.15 K

Let V₂ be the new volume.

[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{300\times 383.15 }{313.15}\\\\V_2=367.06\ cm^3[/tex]

So, the new volume of the balloon is [tex]367.06\ cm^3[/tex].

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.