Answer:
[tex]2 {x}^{3} + 11{x}^{2} - 25x - 28[/tex]
Step-by-step explanation:
Using foil method, Multiply the first term
[tex]2 {x}^{2} \times x = 2 {x}^{3} [/tex]
Next, Multiply the Outer term in each parenthesis. (2x^2 and 7
[tex] 2 {x}^{2} \times 7 = 14 {x}^{2} [/tex]
[tex] 2 {x}^{2} \times 7 = 14 {x}^{2} \: \: \: 3x \times - x = - 3x[/tex]
Then, Multiply the Inner Terms (-3x,-4,7) in each parenthesis
[tex] - 3x \times 7 = - 21x[/tex]
[tex] - 4 \times x = - 4x[/tex]
Then multiply the last term (-4 and 7).
[tex] - 4 \times 7 = - 28[/tex]
Combine it you have
[tex]2 {x}^{3} + 14 {x}^{2} - 3 {x}^{2} - 21x - 4x - 28[/tex]
which simplify to
[tex]2 {x}^{3} + 11 {x}^{2} - 25x - 28[/tex]
