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A baseball stadium holds 15,002 seats. The lower level has 50 fewer than three times as many seats as the upper level. The middle level has 40 more than twice as many seats as the upper level.
x + (2x + 40) + (3x – 50) = 15,002
The upper level has seats.

Sagot :

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U, M, L are the seats in the upper, middle, and lower levels, respectively.
U+M+L = 15,002

L = 3U-50
M = 2U+40

Substitution:
U + (2U+40) + (3U-50) = 15,002
6U - 10 = 15,002
6U = 15,012
U = 2,502

Answer:

The correct answer is 2,502 seats

Step-by-step explanation:

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