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Use the coordinates of the labeled point to find the point-slope equation of
the line
812-18
O A. y + 1 = -2(x - 2)
O B. y-2-2(x+1)
O C. y- 1 = -2(x + 2)
O D. y-2 = 2(x + 1)


Use The Coordinates Of The Labeled Point To Find The Pointslope Equation Of The Line 81218 O A Y 1 2x 2 O B Y22x1 O C Y 1 2x 2 O D Y2 2x 1 class=

Sagot :

Slope of line passing through (x₁, y₁) and (x₂, y₂) = (y₂-y₁)/(x₂-x₁)

(0,3) and (2,-1) are points on the line.
slope = (-1-3)/(2-0) = -2


Point-slope equation for line of slope m that passes through (x₀, y₀):
y-y₀ = m(x-x₀)

m = -2
(x₀, y₀) = (2,-1)
y+1 = -2(x-2)