Adamaljanabi07idn
Answered

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Maya, Ahmad, and Joe served a total of 75 orders Monday at the school cafeteria. Joe served 2 times as many orders as Maya. Ahmad served 5 fewer orders
than Maya. How many orders did they each serve?

Sagot :

LadyStrangeidn

Total number of orders served by Maya, Ahmad and Joe on Moday = 75

Let the number of orders Maya served be x.

Then :

Number of orders Joe served = 2x

Number of orders Ahmad served = x - 5

This can be written in an equation as :

[tex] \tt \: 2x + x - 5 + x = 75[/tex]

[tex] = \tt 4x - 5 = 75[/tex]

[tex] = \tt 4x = 75 + 5[/tex]

[tex] = \tt 4x = 80[/tex]

[tex] = \tt \: x = \frac{80}{4} [/tex]

[tex] = \tt \: x = 20[/tex]

Which means :

Number of orders Joe served :

= 2 × 20

= 40

Thus, Joe served 40 orders.

Number of orders Maya served = 20

Number of orders Ahmad served :

= 20 - 5

= 15

Thus, Ahmad served 15 orders.

Therefore,

  • Maya served 20 orders
  • Ahmad served 15 orders
  • Joe served 40 orders.
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