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Some antacid tables contain aluminum hydroxide. The aluminum hydroxide reacts with stomach acid according to the equation: Al(OH)3 + 3HCl →AlCl3 + 3H2O. Determine the moles of stomach acid (HCl) required if a tablet contains 8.89 moles of Al(OH)3.

Sagot :

Maacastrobridn

Answer:

26.67 mol HCl

Explanation:

Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O

In order to solve this problem, we need to convert Al(OH)₃ moles to HCl moles.

To do so we use the stoichiometric ratios of the balanced reaction:

  • 8.89 mol Al(OH)₃ * [tex]\frac{3molHCl}{1molAl(OH)_{3}}[/tex] = 26.67 mol HCl

Thus 26.67 moles of HCl would react completely with 8.89 moles of Al(OH)₃.

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