Answered

Join the IDNLearn.com community and start getting the answers you need today. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.

The specific heat of water is 4.2j/g ºC how much heat is required to raise the temperature of 100 g of water by 5 ºC

Sagot :

Answer:

116,823 J

Explanation:

formula : q=m C delta T

q = heat = unknown

mass = 100 g

C = specific heat = 4.2 J/K*g

delta T = temperture in Kelvins: 5 + 273.15 = 278.15 K

q = (100 g) ( 4.2 J/K*g) (278.15 K) = 116,823 J

Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.