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A hypothetical element X is found to have an atomic mass of 37.45 amu. Element X has only two isotopes, X-37 and X-38. The X-37 isotope has a fractional abundance of 0.7721 and an isotopic mass of 37.24. What is the isotopic mass of the other isotope?

Sagot :

Answer: The isotopic mass of the other isotope is 38.16 amu

Explanation:

Mass of isotope X-37 = 37.24

fractional abundance of isotope X-37  = 0.7721

Mass of isotope X-38 = ?

fractional abundance of isotope X-38 = (1-0.7721)= 0.2279

Formula used for average atomic mass of an element :

[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]

[tex]37.45=\sum[(37.24\times 0.7721)+(x\times 0.2279)][/tex]

[tex]x=38.16[/tex]

Therefore, the isotopic mass of the other isotope is 38.16 amu

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