Answer:
[tex]120x^4\sqrt{2}[/tex]
Step-by-step explanation:
First we need to break down the numbers in the radicals into its factors
so
12= 3*2*2
x³=x*x*x
Which means we have
[tex]10\sqrt{3*2*2*x*x*x}=20x\sqrt{3x}[/tex]
and
[tex]2\sqrt{2*3*x*x*x*x*x} =2x^{2} \sqrt{6x}[/tex]
Because the radicand (the small number that goes up top) are the same we can just mulitply the two from here
which means we have
[tex](20x*2x^2)\sqrt{3x*6x}=40x^3\sqrt{18x^2} \\\sqrt{18x^2}=\sqrt{2*3*3*x*x} =3x\sqrt{2} \\=120x^4\sqrt{2}[/tex]
