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An object is placed 110 mm from a concave mirror with a focal length of 5.0 cm.

Sagot :

Answer:

Approximately 92 mm.

Explanation:

Object's distance, u = 110 mm = 11 cm

focal length of the mirror = 5 cm

Image distance, v = ?

To determine the image distance, apply the mirror's formula;

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{f}[/tex] - [tex]\frac{1}{u}[/tex]

   = [tex]\frac{1}{5}[/tex] - [tex]\frac{1}{11}[/tex]

   = [tex]\frac{11-5}{55}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{6}{55}[/tex]

⇒ v = [tex]\frac{55}{6}[/tex]

       = 9.166667

v = 9.2 cm

The image distance is 92 mm.

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