Answered

Ask questions, share knowledge, and connect with a vibrant community on IDNLearn.com. Our platform offers reliable and detailed answers, ensuring you have the information you need.

At room temperature , 1 mL of water has a mass of 1 gram . What is the percent by mass of a 428 mL magnesium citrate ( solution containing 0.1 mol of magnesium citrate ?

Sagot :

Jufsanabriasaidn

Answer:

5.0% by mass

Explanation:

Percent by mass is 100 times the ratio between the mass of solute (Magnesium citrate) in the mass of solution.

Mass of Magnesium citrate -Molar mass: 214.41g/mol-:

0.1mol * (214.41g/mol) = 21.441g

Assuming the volume of the solution is just due the solvent -Water-, the mass of water is 428g.

Percent by mass is:

21.441g / 428g * 100 =

5.0% by mass

Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.