Answer:
[tex](a+b)^{2}- \sqrt[3]{x . 3y}[/tex]
Step-by-step explanation:
Subtract the cube root of the product of x and 3y from the square of the sum of a and b.
A = The square of the sum of a and b is [tex](a+b)^{2}[/tex]
B = The cube root of the product of x and 3y is [tex]\sqrt[3]{x . 3y}[/tex]
They want us to subtract B from A so B - A, therefore the following.
[tex](a+b)^{2}- \sqrt[3]{x . 3y}[/tex]
