Hareshassidn
Answered

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Elizabeth has $10, $5, and $1 bills worth $101. she has five more five dollar bills than ten dollar bills and 4 times more 1 dollar bills than 10 dollar bills. How many of each kind of bills does elizabeth have?

Sagot :

Terez99idn

Answer:

Let F = The number of $5 bills and T = the number of $10 bills.  She has 15 bills total, so:

 

F+T = 15                

T = 15-F

 

She has $120 total:

 

$120 = ($5)*F + ($10)*T

$120 = $5*F + ($10)*(15-F)         [Substitute 15-F in place of T]

120 = 5F + 150 - 10F

-30 = -5F

 

6 = F

 

Check:

T= 15-F = 15=6 = 9

 

$120 = ($5)*6 + ($10)*9

$120 = $30 + $90

$120 = $120

Raphealnwobiidn

Elizabeth had 4 of $10 bills, 9 of $5 bills and 16 of $1 bill.

Equation

Let x represent the number of $10 bill, y represent the number of $5 bill and z represent the number of $1 bill. Hence:

10x + 5y + z = 101   (1)

Also:

y = x + 5     (2)

And:

z = 4x    (3)

From equation 1, 2 and 3:

x = 4, y = 9, z = 16

Elizabeth had 4 of $10 bills, 9 of $5 bills and 16 of $1 bill.

Find out more on equation on: https://brainly.com/question/2972832

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