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Answer:
one leg = 5
other leg = 14
Step-by-step explanation:
let 'x' = length of shorter leg
let '2x + 4' = length of longer leg
A = 1/2bh
35 = 1/2x · 2x + 4
35 = x² + 4
x² + 4 - 35 = 0
(x + 7)(x - 5) = 0
x = -7 and x = 5
We can eliminate -7 as an answer since a length cannot be negative
Answer:
The shorter leg = 5
The longer leg = 14
The hypotenuse = 14.866.....
Step-by-step explanation:
if we represent the smaller leg as "x" we firstly represent the longer leg as...
Longer leg = 2x + 4
(We can do this based on the question)
Now we need to undersstadn t in a right angle triangle the legs can be used as a height and base. So we can make the following equation.
[tex]A_{triangle} = \frac{bh}{2}[/tex]
Substitute the lengths of the legs as based and height and get...
[tex]A_{triangle} = \frac{(2x + 4)(x)}{2}[/tex]
[tex]35 = \frac{2x^{2} + 4x}{2}[/tex]
[tex]35 = x^{2} + 2x[/tex]
[tex]35 = x(x + 2)[/tex]
From here we can see that x = 5.
Therefore the lengths are as follows...
The shorter leg = x = 5
The longer leg = 2(5) + 4 = 14
The hypotenuse = [tex]\sqrt{5^{2} + 14^{2} }[/tex]
The hypotenuse = [tex]\sqrt{5^{2} +14^{2} }[/tex]
The hypotenuse = 14.866.....