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Answer:
For producing 0.55 mole of acetic acid, 0.55 mole of ethanol is required.
Explanation:
The balanced equation for this reaction is
CH3CH2OH + O2 --> CH3COOH + H2O
As we can see in this equation, the ration of number of moles of acetic acid to the number of moles of ethanal is equal to [tex]1 : 1[/tex]
Hence, in order to produce one mole of acetic acid, 1 mole of ethanol is required.
Thus, for producing 0.55 mole of acetic acid, 0.55 mole of ethanol is required.