Answered

Explore a wide range of topics and get answers from experts on IDNLearn.com. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.

6 kg block slides to the east across a frictionless surface with a momentum of 30 kg x meters per second strikes an object with an impulse of 10 newtons per second to the west of the block, what is the speed of the block at collission

Sagot :

Answer:

Explanation:

Initial momentum = 30 kg m/s .

impulse on the object = 10 N s towards west . = - 10 Ns

impulse = change in momentum

Let velocity after impulse be v

momentum after impulse = 6 v

change in momentum = 6v - 30

So

- 10 = 6v - 30

20 = 6v

v = 3.33 m /s

Since the velocity is positive , that means it is moving in the same direction as earlier .

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.