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6 kg block slides to the east across a frictionless surface with a momentum of 30 kg x meters per second strikes an object with an impulse of 10 newtons per second to the west of the block, what is the speed of the block at collission

Sagot :

Answer:

Explanation:

Initial momentum = 30 kg m/s .

impulse on the object = 10 N s towards west . = - 10 Ns

impulse = change in momentum

Let velocity after impulse be v

momentum after impulse = 6 v

change in momentum = 6v - 30

So

- 10 = 6v - 30

20 = 6v

v = 3.33 m /s

Since the velocity is positive , that means it is moving in the same direction as earlier .

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