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Answer:
2.9 moles of aluminum sulfate will be produced from the reaction of 5.8 moles of aluminum hydroxide and excess sulfuric acid.
Explanation:
The balanced reaction is:
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Al(OH)₃ produce 1 mole of Al₂(SO₄)₃, then 5.8 moles of Al(OH)₃ how many moles of Al₂(SO₄)₃ will they produce?
[tex]moles of Al_{2} (SO_{4} )_{3} =\frac{5.8moles of Al(OH)_{3} *1 mole of Al_{2} (SO_{4} )_{3}}{2moles of Al(OH)_{3}}[/tex]
moles of Al₂(SO₄)₃= 2.9
2.9 moles of aluminum sulfate will be produced from the reaction of 5.8 moles of aluminum hydroxide and excess sulfuric acid.