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Sagot :
3.59 mol
1.836 x 10 ²⁵ molecules
Further explanation
Given
230 g SO2
30.5 moles LiNO3
Required
moles and molecules
Solution
mol = mass : molar mass
1 mol = 6.02 x 10²³ particles(molecules, atoms, ions)
1. 230 g x 1 mol/64,066 g =3.59 mol
2. 30.5 moles x 6.02 x 10 ²³ molecules / 1 mol = 1.836 x 10 ²⁵ molecules
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