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\sqrt(x^(2)-14x+49)=x-7

Sagot :

Answer:

infinite solutions

Step-by-step explanation:

note the expression inside the radical is a perfect square, that is

x² - 14x + 49 = (x - 7)², then

[tex]\sqrt{x^2-14x+49}[/tex] = x - 7

[tex]\sqrt{(x-7)^2}[/tex] = x- 7, that is

x - 7 = x - 7

Since both sides are the same then any value of x will make the equation true.

The equation has infinite solutions

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