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What is the mass of 4.67 mol of Sulfuric Acid (H2SO4)

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Answer:

458 g H₂SO₄

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

4.67 mol H₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

Step 3: Convert

  1. Set up:                              [tex]\displaystyle 4.67 \ mol \ H_2SO_4(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4})[/tex]
  2. Multiply/Divide:                [tex]\displaystyle 458.08 \ g \ H_2SO_4[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

458.08 g H₂SO₄ ≈ 458 g H₂SO₄

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