Discover how IDNLearn.com can help you learn and grow with its extensive Q&A platform. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
Answer:
1.497 mol Ir
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Chemistry
Atomic Structure
- Reading a Periodic Table
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
287.7 g Ir
Step 2: Identify Conversions
[PT] Molar Mass of Ir - 192.22 g/mol
Step 3: Convert
- Set up: [tex]\displaystyle 287.7 \ g \ Ir(\frac{1 \ mol \ Ir}{192.22 \ g \ Ir})[/tex]
- Multiply/Divide: [tex]\displaystyle 1.49672 \ mol \ Ir[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 4 sig figs.
1.49672 mol Ir ≈ 1.497 mol Ir
Answer:
[tex]\boxed {\boxed {\sf About \ 1.497 \ mol \ Ir }}[/tex]
Explanation:
To convert from grams to moles, we must the molar mass of iridium, which can be found on the Periodic Table.
- Ir: 192.22 g/mol
Use the molar mass as a ratio.
[tex]\frac{ 192.22 \ g \ Ir}{ 1 \ mol \ Ir}[/tex]
Multiply by the given number of grams: 287.7
[tex]287.7 \ g Ir *\frac{ 192.22 \ g \ Ir}{ 1 \ mol \ Ir}[/tex]
Flip the fraction so the grams of Iridium will cancel.
[tex]287.7 \ g Ir *\frac{1 \ mol \ Ir }{ 192.22 \ g \ Ir}[/tex]
[tex]287.7 *\frac{1 \ mol \ Ir }{ 192.22 }[/tex]
[tex]\frac {287.7 \ mol \ Ir }{192.22} \\[/tex]
Divide.
[tex]1.49672251 \ mol \ Ir[/tex]
The original measurement has 4 significant figures, so we must round our answer to 4 sig figs as well. For the answer we calculated, that is the thousandth place.
The 7 in the ten thousandth place tells us to round the 6 up to a 7.
[tex]1.497 \ mol \ Ir[/tex]
There are about 1.497 moles of iridium in 287.7 grams.
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.