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A field is a rectangle with a perimeter of 1240 feet. The length is 400 feet more than the width. Find the width and length of the rectangular field.
The width

A Field Is A Rectangle With A Perimeter Of 1240 Feet The Length Is 400 Feet More Than The Width Find The Width And Length Of The Rectangular Field The Width class=

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Answer:  The length is 510 and the width is 110.

Step-by-step explanation:

To find the area of a rectangle, you will have to add the 2 times the length plus 2 times the width because  a rectangle have 4 sides. Two widths and two  lengths.

You can now use the formula  P= 2l + 2w  

were P is the perimeter , l is the length, and w is the width.

the length is 400 more than the width, so we can represent that by the equation,  l = w + 400  

And now we know that the width is w.

So now we will input the perimeter, length, and into the formula to solve for w.

1240 = 2(w + 400) + 2w

1240 = 2w + 800 + 2w

1240 = 4w + 800

-800            -800

   440 = 4w

    w = 110

L= 110 + 400

L = 510  

Check :

1240 = 2(510) + 2(110)

1240 = 1020 + 220

1240 = 1240

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