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Answer:
See Explanation
Explanation:
The question is incomplete; as the mixtures are not given.
However, I'll give a general explanation on how to go about it and I'll also give an example.
The percentage of a component in a mixture is calculated as:
[tex]\%C_E = \frac{E}{T} * 100\%[/tex]
Where
E = Amount of element/component
T = Amount of all elements/components
Take for instance:
In [tex](Ca(OH)_2)[/tex]
The amount of all elements is: (i.e formula mass of [tex](Ca(OH)_2)[/tex])
[tex]T = 1 * Ca + 2 * H + 2 * O[/tex]
[tex]T = 1 * 40 + 2 * 1 + 2 * 16[/tex]
[tex]T = 74[/tex]
The amount of calcium is: (i.e formula mass of calcium)
[tex]E = 1 * Ca[/tex]
[tex]E = 1 * 40[/tex]
[tex]E = 40[/tex]
So, the percentage component of calcium is:
[tex]\%C_E = \frac{E}{T} * 100\%[/tex]
[tex]\%C_E = \frac{40}{74} * 100\%[/tex]
[tex]\%C_E = \frac{4000}{74}\%[/tex]
[tex]\%C_E = 54.05\%[/tex]
The amount of hydrogen is:
[tex]E = 2 * H[/tex]
[tex]E = 2 * 1[/tex]
[tex]E = 2[/tex]
So, the percentage component of hydrogen is:
[tex]\%C_E = \frac{E}{T} * 100\%[/tex]
[tex]\%C_E = \frac{2}{74} * 100\%[/tex]
[tex]\%C_E = \frac{200}{74}\%[/tex]
[tex]\%C_E = 2.70\%[/tex]
Similarly, for oxygen:
The amount of oxygen is:
[tex]E = 2 * O[/tex]
[tex]E = 2 * 16[/tex]
[tex]E = 32[/tex]
So, the percentage component of oxygen is:
[tex]\%C_E = \frac{E}{T} * 100\%[/tex]
[tex]\%C_E = \frac{32}{74} * 100\%[/tex]
[tex]\%C_E = \frac{3200}{74}\%[/tex]
[tex]\%C_E = 43.24\%[/tex]